**Given the quadratic function x2-6x+8=0 Find the x and y**

The graphs of quadratic functions are called parabolas. Here are some examples of parabolas. All parabolas are vaguely “U” shaped and they will have a highest or lowest point that is called the vertex. Parabolas may open up or down and may or may not have \(x\)-intercepts and they will always have a single \(y\)-intercept. Note as well that a parabola that opens down will always open down... To find the y-intercept of this parabola all you need to do is set x to zero (because the y-intercept is on the y-axis where x = 0). If we do this with the vertex form of a parabola we will have: y = a (0 – h ) 2 + k

**calculus Maximum x-intercept with a parabola and**

18/05/2010 · Now to find the y intercepts, make x= 0.. to get y = 8, therefore the y intercept is (0, 8). Now for the vertex, take the derivative and set it to 0: 2x - 6 = 0... Question 611676: I need some help on this im just not getting it at all. Find the x-intercepts of the parabola with vertex (3,-2) and y- intercept (0,7).

**Finding the function of a Parabola Physics Forums**

Question 611676: I need some help on this im just not getting it at all. Find the x-intercepts of the parabola with vertex (3,-2) and y- intercept (0,7).... The graphs of quadratic functions are called parabolas. Here are some examples of parabolas. All parabolas are vaguely “U” shaped and they will have a highest or lowest point that is called the vertex. Parabolas may open up or down and may or may not have \(x\)-intercepts and they will always have a single \(y\)-intercept. Note as well that a parabola that opens down will always open down

**Finding the function of a Parabola Physics Forums**

To find the y-intercept of this parabola all you need to do is set x to zero (because the y-intercept is on the y-axis where x = 0). If we do this with the vertex form of a parabola we will have: y = a (0 – h ) 2 + k... 18/05/2010 · Now to find the y intercepts, make x= 0.. to get y = 8, therefore the y intercept is (0, 8). Now for the vertex, take the derivative and set it to 0: 2x - 6 = 0

## How To Find The X Intercept Of A Parabola Function

### Given the quadratic function x2-6x+8=0 Find the x and y

- Finding the function of a Parabola Physics Forums
- calculus Maximum x-intercept with a parabola and
- calculus Maximum x-intercept with a parabola and
- Given the quadratic function x2-6x+8=0 Find the x and y

## How To Find The X Intercept Of A Parabola Function

### Question 611676: I need some help on this im just not getting it at all. Find the x-intercepts of the parabola with vertex (3,-2) and y- intercept (0,7).

- I know how to find extrema of a function, however, I'm wondering how calculus would approach finding the maximum x-intercept achieved given a parametric function representing a parabola (or at least the first derivative so that the max distance achieved has a derivative of zero).
- Even more generally, the y intercept of f(x) is f(0), at least if 0 belongs to the domain of the function f. For example, the function [math]\sqrt{x-1}[/math] does not have a y intercept since 0 does not have a function …
- 18/05/2010 · Now to find the y intercepts, make x= 0.. to get y = 8, therefore the y intercept is (0, 8). Now for the vertex, take the derivative and set it to 0: 2x - 6 = 0
- Even more generally, the y intercept of f(x) is f(0), at least if 0 belongs to the domain of the function f. For example, the function [math]\sqrt{x-1}[/math] does not have a y intercept since 0 does not have a function …

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